Wrong Answer fix
ＢＥＣＣＡ · 2013-12-23 13:04:36
For those who getting WA. Just write the code for this problem and accept it :)
Description
A simple mathematical formula for e is
e=?0<=i<=n1/i!
where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small
values of n.
Input
No input
Output
Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of
your output should appear similar to that shown below.
Sample Input
no input
Sample Output
n e
- -----------
0 1
1 2
2 2.5
3 2.666666667
4 2.708333333
...
Daneshvar Amrollahi · 2014-01-20 20:24:11
Hi. Can anyone tell me why am I getting WA? This is my code:
#include<iostream>
#include<iomanip>
using namespace std;
unsigned long long int fact(int n)
{
if (n==0)
return 1;
else
return n*fact(n-1);
}
int main()
{
int n;
double ans;
cout<<1<<endl<<2<<endl<<2.5<<endl;
for (int k=3;k<=9;k++)
{
ans = 0;
for (int i=0;i<=k;i++)
ans+=(1/double(fact(i)));
cout<<fixed<<setprecision(9)<<ans<<endl;
}
return 0;
}
Daneshvar Amrollahi · 2014-01-22 20:29:19
･BECCA can make １＝＝３ anyway said:
For those who getting WA. Just write the code for this problem and accept it :)
Description A simple mathematical formula for e is e=?0<=i<=n1/i! where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n. Input No input Output Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below. Sample Input no input Sample Output n e - ----------- 0 1 1 2 2 2.5 3 2.666666667 4 2.708333333 ...･BECCA can make １＝＝３ anyway said:
For those who getting WA. Just write the code for this problem and accept it :)
Description A simple mathematical formula for e is e=?0<=i<=n1/i! where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n. Input No input Output Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below. Sample Input no input Sample Output n e - ----------- 0 1 1 2 2 2.5 3 2.666666667 4 2.708333333 ...
Can you tell me why is this wrong?
cout<<"1"<<endl;
cout<<"2"<<endl;
cout<<"2.5"<<endl;
cout<<"2.666666667"<<endl;
cout<<"2.708333333"<<endl;
cout<<"2.716666667"<<endl;
cout<<"2.718055556"<<endl;
cout<<"2.718253968"<<endl;
cout<<"2.71827877"<<endl;
cout<<"2.718281526";
ＢＥＣＣＡ · 2014-01-22 23:39:31
Hello!
No.
Your output should exactly look like this:
cout << "n e" << endl;
cout << "- -----------" << endl;
cout << "0 1" << endl;
cout << "1 2" << endl;
cout << "2 2.5" << endl;
cout << "3 2.666666667" << endl;
cout << "4 2.708333333" << endl;
cout << "5 2.716666667" << endl;
cout << "6 2.718055556" << endl;
cout << "7 2.718253968" << endl;
cout << "8 2.718278770" << endl;
cout << "9 2.718281526" << endl;
Daneshvar Amrollahi · 2014-01-23 07:25:17
･BECCA can make １＝＝３ anyway said:
Hello!
No.
Your output should exactly look like this:
cout << "n e" << endl; cout << "- -----------" << endl; cout << "0 1" << endl; cout << "1 2" << endl; cout << "2 2.5" << endl; cout << "3 2.666666667" << endl; cout << "4 2.708333333" << endl; cout << "5 2.716666667" << endl; cout << "6 2.718055556" << endl; cout << "7 2.718253968" << endl; cout << "8 2.718278770" << endl; cout << "9 2.718281526" << endl;
The problem did not say anything about this kind of output! Thanks. It worked.
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